document.write( "Question 763418: I need to know what a parabola graph looks like when the parabola will cross the x-axis at 0 and 12. I worked out the problem I just need to know what the graph will look like. I don't understand that part of it.\r
\n" ); document.write( "\n" ); document.write( "My problem was: -25x^2 + 300x = 0
\n" ); document.write( " 25x^2 - 300x = 0
\n" ); document.write( " 25x (x - 12) = 0
\n" ); document.write( " 25x = 0 or x -12 = 0
\n" ); document.write( "I just need to know how to graph it and see what it looks like. I believe the parabola will open downward because it has a negative value. \n" ); document.write( "

Algebra.Com's Answer #464782 by ramkikk66(644) $\"\"$ $\"About$

You can put this solution on YOUR website!
Your solution is right. The quadratic has two roots x = 0 and x = 12.\r
\n" ); document.write( "\n" ); document.write( "See the graph below (I have divided the eqn by 25 to make -x^2 + 12*x = 0, which has the same 2 roots, to make it fit.) You are right that the graph opens downwards. It has a max value for x = 6.\r
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\n" ); document.write( "\n" ); document.write( ":)\r
\n" ); document.write( "\n" ); document.write( " $\"graph%28+600%2C+600%2C+-20%2C+20%2C+-50%2C+50%2C+-x%5E2+%2B+12%2Ax+%2B+0%29\"$ \n" ); document.write( "

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