document.write( "Question 763367: 1/2logbase10 25-2logbase10 3+logbase10 18 \n" ); document.write( "
Algebra.Com's Answer #464743 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! 1/2logbase10 25-2logbase10 3+logbase10 18 \n" ); document.write( "Move the integers (1/2 and 2) to front and make them powers \n" ); document.write( "logbase10 25^1/2 - logbase10 3^2 + logbase10 18 \n" ); document.write( "25^1/2 = square root of 25 \n" ); document.write( "logbase10 5 - logbase10 9 + logbase10 18\r \n" ); document.write( "\n" ); document.write( "logbase10 5 * 18/9 \n" ); document.write( "logbase10 10 = 1 \n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |