document.write( "Question 763367: 1/2logbase10 25-2logbase10 3+logbase10 18 \n" ); document.write( "
Algebra.Com's Answer #464743 by Cromlix(4381)\"\" \"About 
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1/2logbase10 25-2logbase10 3+logbase10 18
\n" ); document.write( "Move the integers (1/2 and 2) to front and make them powers
\n" ); document.write( "logbase10 25^1/2 - logbase10 3^2 + logbase10 18
\n" ); document.write( "25^1/2 = square root of 25
\n" ); document.write( "logbase10 5 - logbase10 9 + logbase10 18\r
\n" ); document.write( "\n" ); document.write( "logbase10 5 * 18/9
\n" ); document.write( "logbase10 10 = 1
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-)
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