document.write( "Question 763339: Tom and Gary are leaving the same town for a meeting in different cities. However, they have not quite finished discussing a business plan. Tom must leave 1 1/2 hours earlier then Gary to make his meeting. Tom heads east on a train at 55 miles per hour. Gary heads west on a train at 70 miles per hour. How long can they talk on their phones if the phones have a range of 276.25 miles? \n" ); document.write( "
Algebra.Com's Answer #464730 by ramkikk66(644)\"\" \"About 
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Tom and Gary are leaving the same town for a meeting in different cities. However, they have not quite finished discussing a business plan. Tom must leave 1 1/2 hours earlier then Gary to make his meeting. Tom heads east on a train at 55 miles per hour. Gary heads west on a train at 70 miles per hour. How long can they talk on their phones if the phones have a range of 276.25 miles?\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "Tom travels for 1.5 hours before Gary starts. In that time he travels 55*1.5 = 82.5 miles\r
\n" ); document.write( "\n" ); document.write( "After that, since they travel in opposite directions, the distance between them increases by (55+70) = 125 miles every hour.\r
\n" ); document.write( "\n" ); document.write( "Let us say than can talk for x hours before they go out of range.\r
\n" ); document.write( "\n" ); document.write( "Since the initial gap between them is 82.5, and it increases by 125 every hour, we have the equation\r
\n" ); document.write( "\n" ); document.write( "\"82.5+%2B+125%2Ax+=+276.25\"\r
\n" ); document.write( "\n" ); document.write( "\"125%2Ax+=+193.75\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+193.75%2F125+=+1.55\"\r
\n" ); document.write( "\n" ); document.write( "So they can talk for another \"highlight%281.55%29\" hours or 1 hour and 33 minutes.\r
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