document.write( "Question 763308: How do I solve\r
\n" ); document.write( "\n" ); document.write( "9 + 3x
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\n" ); document.write( "\n" ); document.write( "x\"2 -9
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Algebra.Com's Answer #464682 by algebrahouse.com(1659)\"\" \"About 
You can put this solution on YOUR website!
9 + 3x
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\n" ); document.write( "x² - 9\r
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\n" ); document.write( "\n" ); document.write( "3x + 9
\n" ); document.write( "-------------- {re-arranged numerator and factored denominator into two binomials}
\n" ); document.write( "(x + 3)(x - 3)\r
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\n" ); document.write( "\n" ); document.write( "3(x + 3)
\n" ); document.write( "-------------- {factored 3 out of numerator}
\n" ); document.write( "(x + 3)(x - 3)\r
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\n" ); document.write( "\n" ); document.write( "3
\n" ); document.write( "----- {cancelled (x + 3) in numerator and denominator}
\n" ); document.write( "x - 3
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For more help from me, visit: www.algebrahouse.com


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