document.write( "Question 763308: How do I solve\r
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document.write( "9 + 3x
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document.write( "x\"2 -9 \n" );
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Algebra.Com's Answer #464682 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! 9 + 3x \n" ); document.write( "------ \n" ); document.write( "x² - 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 9 \n" ); document.write( "-------------- {re-arranged numerator and factored denominator into two binomials} \n" ); document.write( "(x + 3)(x - 3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3(x + 3) \n" ); document.write( "-------------- {factored 3 out of numerator} \n" ); document.write( "(x + 3)(x - 3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 \n" ); document.write( "----- {cancelled (x + 3) in numerator and denominator} \n" ); document.write( "x - 3 \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " \n" ); document.write( " |