document.write( "Question 763272: I don't know how to solve the following inequality: 3x-2 over x+3 is less than or equal to 2
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Algebra.Com's Answer #464667 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
Solve
\n" ); document.write( "(1) \"%283x-2%29%2F%28x%2B3%29%3C=+2\"
\n" ); document.write( "Start by multiplying both sides of the inequality by the denominator (x+3) and get
\n" ); document.write( "(2)\"%28x%2B3%29%2A%283x-2%29%2F%28x%2B3%29%3C=+2%2A%28x%2B3%29\" or
\n" ); document.write( "(3)\"%283x-2%29%3C=+2x+%2B6\" or
\n" ); document.write( "(4)\"x+%3C=+2%2B6\" or
\n" ); document.write( "(5)\"x+%3C=+8\"
\n" ); document.write( "Check this with x ={0,8,10}
\n" ); document.write( "Is (\"%283%2A0-2%29%2F%280%2B3%29%3C=+2\") True?
\n" ); document.write( "Is (\"-2%2F3%3C=+2\") True? Yes
\n" ); document.write( "Is (\"%283%2A8-2%29%2F%288%2B3%29%3C=+2\") True?
\n" ); document.write( "Is (\"22%2F11%3C=+2\") True? Yes
\n" ); document.write( "Is (\"%283%2A10-2%29%2F%2810%2B3%29%3C=+2\") True?
\n" ); document.write( "Is (\"28%2F13%3C=+2\") True? No
\n" ); document.write( "Solution: \"x+%3C=+8\"
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