document.write( "Question 763244: A sequence \"a%5Bn%5D\" satisfies following condition.
\n" ); document.write( "Calculate \"lim%28+x-%3Einfinity%2C+a%5Bn%5D+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"a%5B1%5D=3\", \"a%5Bn%2B1%5D=%282%2F3%29%2Aa%5Bn%5D+%2B+%281%2F4%29\" (n=1,2,3...)
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Algebra.Com's Answer #464661 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
Let's assume that in the limit (a sub n) becomes a constant value c. then we have
\n" ); document.write( "(1) c = (2/3)*c + (1/4) or
\n" ); document.write( "(2) (1-2/3)*c = 1/4 or
\n" ); document.write( "(3) (1/3)*c = 1/4 or
\n" ); document.write( "(4) c = 3*(1/4) or
\n" ); document.write( "(5) c = 3/4 voila!!!
\n" ); document.write( "Check it
\n" ); document.write( "Is (3/4 = (2/3)*(3/4) + 1/4)?
\n" ); document.write( "Is (3/4 = 1/2 + 1/4)?
\n" ); document.write( "Is (3/4 = 3/4)? Yes
\n" ); document.write( "Answer: In the limit as n goes to infinity a sub n goes to 3/4.
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