document.write( "Question 763263: Find the area of the shaded portion in the equilateral triangle with sides 6.\r
\n" ); document.write( "\n" ); document.write( "(assuming the central point of each arc is its corresponding \r
\n" ); document.write( "\n" ); document.write( "vertex)https://media.glynlyon.com/g_geo_2012/8/groupi56.gif
\n" ); document.write( "

Algebra.Com's Answer #464653 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "you need to use the area of \"Sector of the circle\" formula
\n" ); document.write( "
\n" ); document.write( "\"A=%28n%2F360%29r%5E2%2Api\" where n is the number of degrees in the central angle of the sector \r
\n" ); document.write( "\n" ); document.write( "your shaded area is equal to area of the triangle minus area of three sectors of the circle\r
\n" ); document.write( "\n" ); document.write( "area of the triangle:\r
\n" ); document.write( "\n" ); document.write( "sides length: \"a=6\",\"b=6\",\"c=6\"\r
\n" ); document.write( "\n" ); document.write( "find height \"h\" which divides triangle into two right angle triangles whose sides are: hypotenuse \"6\", one leg is \"a%2F2=3\" and other leg is \"h\"\r
\n" ); document.write( "\n" ); document.write( "so, \"h%5E2=6%5E2-3%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"h%5E2=36-9\"\r
\n" ); document.write( "\n" ); document.write( "\"h%5E2=27\"\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%2827%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h=5.196\"\r
\n" ); document.write( "\n" ); document.write( "now we can find the area of triangle \"A%5Bt%5D\":\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bt%5D=%281%2F2%29a%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bt%5D=%281%2F2%296%2A5.196\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bt%5D=3%2A5.196\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bt%5D=15.588\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "now find area of circle sector:\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bcs%5D=%28n%2F360%29r%5E2%2Api\"........\"n=60\", \"r=3\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bcs%5D=%2860%2F360%293%5E2%2A3.14\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bcs%5D=%281%2F6%299%2A3.14\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bcs%5D=28.26%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bcs%5D=4.71\"\r
\n" ); document.write( "\n" ); document.write( "you have three of these sectors, so total area is \"3A%5Bcs%5D=3%2A4.71\"\r
\n" ); document.write( "\n" ); document.write( "\"3A%5Bcs%5D=14.13\"\r
\n" ); document.write( "\n" ); document.write( "now we can find the area of the shaded portion: it is equal to difference between the area of the triangle and three sectors\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A%5Bshaded_portion%5D=A%5Bt%5D-3A%5Bcs%5D=15.588-14.13\"\r
\n" ); document.write( "\n" ); document.write( "\"A%5Bshaded_portion%5D=A%5Bt%5D-3A%5Bcs%5D=1.458\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );