document.write( "Question 64609: sqrt(2x-1) - sqrt(x+3) = 1 \n" ); document.write( "
Algebra.Com's Answer #46463 by praseenakos@yahoo.com(507)![]() ![]() You can put this solution on YOUR website! QUESTION:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sqrt(2x-1) - sqrt(x+3) = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ANSWER:\r \n" ); document.write( "\n" ); document.write( "sqrt(2x-1) - sqrt(x+3) = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Squaring on both sides,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(sqrt(2x-1) - sqrt(x+3))^2 = 1^2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2x-1) + (x+3)- 2 sqrt[ (2x-1)(x+3) ] = 1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x-1 + x+3 - 2 sqrt[ 2x*x + 2x* 3- 1 * x -1 * 3 ] = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + x - 1 + 3 - 2 sqrt[2x^2 + 6x - x - 3 ] = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 2 - 2sqrt [2x^2 + 5x -3] = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 2 - 1 = 2sqrt [2x^2 + 5x -3] \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 1 = 2sqrt [2x^2 + 5x -3] \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Squaring again,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(3x + 1 )^2 = (2sqrt [2x^2 + 5x -3] )^2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x^2 + 6x + 1 = 4 [2x^2 + 5x -3]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x^2 + 6x + 1 = 4 * 2x^2 + 4 *5x - 4*3 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x^2 + 6x + 1 = 8x^2 + 20x - 12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9x^2 -8x^2 + 6x - 20x + 1 + 12 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1x^2 - 14x + 13 = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 14x + 13 = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is a quadratic equation,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For solving this equation we have different methods - 1)Using quadratic formula 2) Splitting middle term.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Splitting middile term:\r \n" ); document.write( "\n" ); document.write( "x^2 - 14x + 13 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here we have to find out two numbers whose sum is -14 and product is +13. \n" ); document.write( "Such two numbers are -13 and -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> x^2 - 13x - 1x+ 13 = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> ( x^2 - 13x )- (1x - 13 ) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> x (x -13) -1(x-13) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take out common terms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> (x-13)(x-1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> either (x-13)= 0 or (x-1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> x = 13 or x = 1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the solution is x = 13 or x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. Quadratic formula:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The general form of a quadratic equation is ax^2 + bx + c = 0 and its solution is given by the formula,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here we have a = 1, b = -14 and c = 13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute these values in (1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We have, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> x = (14 + 12 )/ 2 or x = (14 - 12 )/ 2 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> x = 26/2 or x = 2/2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "==> x = 13 or x = 1\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In both cases we can see that answers are same.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope you understood.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Regards.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Praseena.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |