document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=763182>Question 763182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using logs 3^2n = 3 x 6^n+3. Please show your work.\r<BR>\n" );
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document.write( "I somehow got n= (2log3 - log2)/(3log6), however, <BR>\n" );
document.write( "the correct answer is n= (log3 + 3log6)/(2log3 - log6)\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464605 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464605\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve using logs 3^2n = 3*6^n+3. Please show your work.<BR>\n" );
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document.write( "2n*log(3) = log(3) + (n+3)*log(6) = log(3) + n*log(6) + 3*log(6)<BR>\n" );
document.write( "2n*log(3) - n*log(6) = log(3) + 3log(6)<BR>\n" );
document.write( "n*(2log(3) - log(6)) = log(3) + 3log(6)<BR>\n" );
document.write( "n = (log3 + 3log6)/(2log3 - log6) (as below)<BR>\n" );
document.write( "n = log(648)/log(1.5)<BR>\n" );
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document.write( "\n" );
document.write( "I somehow got n= (2log3 - log2)/(3log6), however, <BR>\n" );
document.write( "the correct answer is n= (log3 + 3log6)/(2log3 - log6)<BR>\n" );
document.write( " </SPAN>\n" );
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