document.write( "Question 763168: If Log 5= m and Log 7=n, determine log 35/10 (35 over 10) in terms of m and n.\r
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document.write( "When I tried by myself I got (m+n)/10, according to the correct answer I should have m+n-1.\r
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document.write( "Thank you for the help! \n" );
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Algebra.Com's Answer #464584 by ramkikk66(644) ![]() You can put this solution on YOUR website! I'm assuming the logarithms m and n are to the base 10.\r \n" ); document.write( "\n" ); document.write( "Applying the basic laws of logs i.e. \n" ); document.write( "Log (A*B) = Log A + log B \n" ); document.write( "Log (A/B) = Log A - Log B\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log (35/10) = log 35 - log 10 \r \n" ); document.write( "\n" ); document.write( "= log (5*7) - log 10 \n" ); document.write( "= log 5 + log 7 - log 10\r \n" ); document.write( "\n" ); document.write( "= m + n - 1 (because log 10 to the base 10 = 1)\r \n" ); document.write( "\n" ); document.write( "So the correct answer is indeed \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( " |