document.write( "Question 763142: log3(2x+3)=4-log3(x+0)solve for x\r
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document.write( "log 3 = log subscript 3...I can't write it in the correct way sorry. \n" );
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Algebra.Com's Answer #464576 by lwsshak3(11628) ![]() You can put this solution on YOUR website! log3(2x+3)=4-log3(x+0)solve for x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "convert to exponential form \n" ); document.write( "3^4=(2x+3)(x+0) \n" ); document.write( "81=2x^2+3x \n" ); document.write( "2x^2+3x-81=0 \n" ); document.write( "solve for x by quadratic formula: \n" ); document.write( " \n" ); document.write( "a=2, b=3, c=-81 \n" ); document.write( "ans: \n" ); document.write( "x≈-7.158 (reject, x>0) \n" ); document.write( "or \n" ); document.write( "x≈5.658 \n" ); document.write( " |