document.write( "Question 65741: The amount of water remaining after t days is given by A=A0e^-0.18 where A0 is the starting amount at the beginning of the time period. How much should be acquired now to have 40 grams remaining after 3 days? \n" ); document.write( "
Algebra.Com's Answer #46457 by ankor@dixie-net.com(22740)\"\" \"About 
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The amount of water remaining after t days is given by A=A0e^-0.18 where A0 is the starting amount at the beginning of the time period. How much should be acquired now to have 40 grams remaining after 3 days?
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\n" ); document.write( "The formula A = Ao*e^-.18 seems to be missing the time factor t:
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\n" ); document.write( "I assume it is A = Ao * e^-.18t
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\n" ); document.write( "Substitute for A and t:
\n" ); document.write( "40 = Ao * e^(-.18*3)
\n" ); document.write( "40 = Ao * e^-.54
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\n" ); document.write( "Find e^-.54 on a good calc:
\n" ); document.write( "40 = Ao * .582748
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\n" ); document.write( "Ao = 40/.582748
\n" ); document.write( "Ao = 68.64 grams is the initial amt\r
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