document.write( "Question 65741: The amount of water remaining after t days is given by A=A0e^-0.18 where A0 is the starting amount at the beginning of the time period. How much should be acquired now to have 40 grams remaining after 3 days? \n" ); document.write( "

Algebra.Com's Answer #46455 by josmiceli(19441) $\"\"$ $\"About$

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$\"A+=+A%5B0%5De%5E%28-.18t%29\"$
\n" ); document.write( " $\"40+=+A%5B0%5De%5E%28-.18%2A3%29\"$
\n" ); document.write( " $\"A%5B0%5D+=+40%2A%281%2Fe%5E%28-.54%29%29\"$
\n" ); document.write( " $\"ln%28A%5B0%5D%29+=+ln%2840%29+%2B+.54\"$
\n" ); document.write( " $\"ln%28A%5B0%5D%29+=+3.689+%2B+.54\"$
\n" ); document.write( " $\"ln%28A%5B0%5D%29+=+4.229+\"$
\n" ); document.write( " $\"A%5B0%5D+=+68.649\"$ grams answer
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