document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762638>Question 762638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-2y=5 x and y intercept </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464544 by </B><A HREF=/tutors/aboutme.mpl?userid=2897696><B>2897696(96)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=2897696><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=2897696><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> change equation into  linear equation form: y=mx+b (basically solving for y)<BR>\n" );
document.write( "y=y coordinate<BR>\n" );
document.write( "m=slope<BR>\n" );
document.write( "x=x coordinate<BR>\n" );
document.write( "b=y intercept<BR>\n" );
document.write( "2x-2y=5 =>2x-2x-2y=-2x+5 get y by self, so move x over first<BR>\n" );
document.write( "-2y=-2x+5 => (1/-2)(-2y)= -2x(1/-2)+ 5(1/-2)now move -2 to the other side, by dividing -2 to the -2x &5<BR>\n" );
document.write( "y=x+(5/-2) this is now in linear form: y=mx+b<BR>\n" );
document.write( "y=y<BR>\n" );
document.write( "m=1<BR>\n" );
document.write( "x=x<BR>\n" );
document.write( "b=5/-2 *since b is the y intercept, the y intercept is (0,5/-2)<BR>\n" );
document.write( "Answer: (0,5/-2) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );