document.write( "Question 64614: Given f(x)=1/x and g(x)=(x+1)/(x-2), find f/g(x) and state its domain. \n" ); document.write( "
Algebra.Com's Answer #46454 by praseenakos@yahoo.com(507)\"\" \"About 
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QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "Given f(x)=1/x and g(x)=(x+1)/(x-2), find f(x)/ g(x) and state its domain.\r
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\n" ); document.write( "\n" ); document.write( "f(x)/ g(x) = (1/x )/ ((x+1)/(x-2))\r
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\n" ); document.write( "\n" ); document.write( "While dividing two rational expressions, take the reciprocal of the divisor(that is f(x)) and multiply it with the divident ( that is g(x) )\r
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\n" ); document.write( "\n" ); document.write( "==> f(x)/ g(x) = (1/x )* [(x-2)/(x+1)]\r
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\n" ); document.write( "\n" ); document.write( "==> = [ 1 * (x-2)]/[x * (x+1)]\r
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\n" ); document.write( "\n" ); document.write( "==> = (x-2)/( x*x - x*1)\r
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\n" ); document.write( "\n" ); document.write( "==> f(x)/ g(x) = ( x-2)/(x^2 -x )\r
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\n" ); document.write( "\n" ); document.write( "OR we can write, f(x)/ g(x) = (x-2)/x(x + 1)\r
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\n" ); document.write( "\n" ); document.write( "In the denominator, we have x(x + 1)\r
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\n" ); document.write( "\n" ); document.write( "The values, x = 0 and x = -1 make the denominator zero.\r
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\n" ); document.write( "\n" ); document.write( "That means for values, x = 0, -1 the function is not defined.\r
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\n" ); document.write( "\n" ); document.write( "So we can say that domain of f(x)/ g(x) is set of all real numbers except 0 and -1\r
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\n" ); document.write( "\n" ); document.write( "That is Domain = R - {0, -1}\r
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\n" ); document.write( "\n" ); document.write( "Hope you understood.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.
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