document.write( "Question 763130: A rectangle's Widith is one-third its length, and its perimeter is 88m. Find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #464524 by ramkikk66(644) $\"\"$ $\"About$

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Let the breadth (width) be x metres. \r
\n" ); document.write( "\n" ); document.write( "As width is one third of length, the length will be 3x metres. \r
\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle = $\"2%28l%2Bb%29\"$ \r
\n" ); document.write( "\n" ); document.write( "So, perimeter = $\"2%2A%28x%2B3x%29\"$ = $\"2%2A4x+=+8x+metres\"$ \r
\n" ); document.write( "\n" ); document.write( "It is given that perimeter is 88m.\r
\n" ); document.write( "\n" ); document.write( "So, 8*x = 88\r
\n" ); document.write( "\n" ); document.write( " $\"x=11+metres.\"$ \r
\n" ); document.write( "\n" ); document.write( "So, dimensions are 11m and 11*3 = 33m.\r
\n" ); document.write( "\n" ); document.write( "Length = 33m, Width = 11m\r
\n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( "

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