document.write( "Question 763111: How many kids out of 27 chose a 2 dip cone and how many chose a 3 dip cone if there were 70 dips total and 27 cones counted?
\n" ); document.write( "What are the equations? thanks. \n" ); document.write( "

Algebra.Com's Answer #464514 by josgarithmetic(39630) $\"\"$ $\"About$

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27 kids means 27 cones.\r
\n" ); document.write( "\n" ); document.write( "Let u = how many 2 dip cones
\n" ); document.write( "Let v = how many 3 dip cones\r
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\n" ); document.write( "\n" ); document.write( "Accounting for cones, $\"u%2Bv=27\"$ \r
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\n" ); document.write( "\n" ); document.write( "Accounting for dips, $\"2%2Au%2B3%2Av=70\"$
\n" ); document.write( "In case confusion how this one works, 2 dips per cone multiplied by how many 2-dip cones PLUS 3 dips per cone multiplied by how many 3-dip cones IS 70 dips.\r
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\n" ); document.write( "\n" ); document.write( "Solve this system for u and v:
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\n" ); document.write( "{u+v=27}
\n" ); document.write( "{2u+3v=70}
\n" ); document.write( "-------------------------------\r
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\n" ); document.write( "\n" ); document.write( "Solve however you want. A way is, multiply the first equation by 2 and subtract from the second equation, and solve first for v.
\n" ); document.write( "then,... \n" ); document.write( "

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