document.write( "Question 762980: A football player stands at a distance c behind the middle of the goal. He sees the angle of elevation of the nearer crossbar to be u and that the distance of the farther one to be v. Show that the distance between the goals is c(tanu cotv - 1. Thank you very much. \n" ); document.write( "
Algebra.Com's Answer #464509 by KMST(5379)\"\" \"About 
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Drawing (not to scale):
\n" ); document.write( " The player's eye is at P. The goal posts are red, with crossbars at Q and R.
\n" ); document.write( "The blue lines are the player's horizontal line of sight, and the player's lines of sight to the crossbars of the two goal posts.
\n" ); document.write( "angle u = angle QPS
\n" ); document.write( "angle v = angle RPT
\n" ); document.write( "c = PS
\n" ); document.write( "QS = RT = height of goal post crossbar
\n" ); document.write( "ST = distance between goalposts
\n" ); document.write( "\"tan%28u%29=QS%2FPS\" --> \"tan%28u%29=QS%2Fc\" --> \"c%2Atan%28u%29=QS\"
\n" ); document.write( "\"cot%28v%29=PT%2FRT\" --> \"cot%28v%29=PT%2FQS\" --> \"QS%2Acot%28v%29=PT\" --> \"PT=c%2Atan%28u%29%2Acot%28v%29\"
\n" ); document.write( "\"ST=PT-PS\" --> \"ST=PT-c\" --> \"ST=c%2Atan%28u%29%2Acot%28v%29-c\" --> \"ST=c%28tan%28u%29%2Acot%28v%29-1%29\"
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\n" ); document.write( "EXTRA:
\n" ); document.write( "If a regular polygon with \"n\" sides is circumscribed around a circle,
\n" ); document.write( "connecting the vertices to the center will give you \"n\" isosceles triangles whose vertex angles measure \"360%5Eo%2Fn\".
\n" ); document.write( "Then, connecting to the center the point of tangency at the midpoint of the sides will split each of those isosceles triangles into two congruent right triangles, with angles measuring \"360%5Eo%2F2n\" at the center of the circle.
\n" ); document.write( " In the right triangle \"side%2F2=R%2Atan%28360%5Eo%2F10%29\" (for the pentagon in the drawing)
\n" ); document.write( "From this point, you can calculate the perimeter of the polygon, and the area of each triangle. Then, adding the areas of the triangles you get the area of the polygon.
\n" ); document.write( "
\n" ); document.write( "For the pentagon in the drawing,
\n" ); document.write( "\"side%2F2=R%2Atan%2836%5Eo%29\" --> \"side=2R%2Atan%2836%5Eo%29\"
\n" ); document.write( "\"Perimeter=5%2A2R%2Atan%2836%5Eo%29\" --> \"Perimeter=10%2AR%2Atan%2836%5Eo%29\"
\n" ); document.write( "With \"R=100feet\", we calculate the approximate value as \"Perimeter=10%2A100feet%2Atan%2836%5Eo%29=1000%2A0.7265feet=726.5feet\" (or maybe \"727feet\").
\n" ); document.write( "For each red isosceles triangle in the pentagon in the drawing,
\n" ); document.write( "
\n" ); document.write( "and for the whole pentagon
\n" ); document.write( "\"area=5R%5E2%2Atan%2836%5Eo%29\" is approximately \"area=5%2A%28100feet%29%5E2%2A0.72654=36327feet%5E2\"
\n" ); document.write( "
\n" ); document.write( "For a decagon, \"n=10\"
\n" ); document.write( "\"side%2F2=R%2Atan%28360%5Eo%2F20%29\" --> \"side%2F2=R%2Atan%2818%5Eo%29\" --> \"side=2R%2Atan%2818%5Eo%29\"
\n" ); document.write( "\"Perimeter=10%2A2R%2Atan%2818%5Eo%29\" --> \"Perimeter=20%2AR%2Atan%2836%5Eo%29\"
\n" ); document.write( "With \"R=100feet\", we calculate the approximate value as \"Perimeter=20%2A100feet%2Atan%2818%5Eo%29=2000%2A0.3249feet=649.8feet\" (or maybe \"650feet\").
\n" ); document.write( "For each red isosceles triangle in the decagon,
\n" ); document.write( "
\n" ); document.write( "and for the whole decagon
\n" ); document.write( "\"area=10R%5E2%2Atan%2818%5Eo%29\" is approximately \"area=10%2A%28100feet%29%5E2%2A0.32492=32492feet%5E2\"
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