document.write( "Question 763112: Find the nth-degree polynomial function with real coefficients satisfying the given conditions.
\n" ); document.write( "n=4; i and 5i are zeros; f(-1)=52\r
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Algebra.Com's Answer #464507 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
Since coefficients are real this must mean that the complex roots occur in conjugate pairs. We can write:\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Af%28x%29=a%28x-i%29%28x%2Bi%29%28x-5i%29%28x%2B5i%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "and given that f(-1)=52 we can determine a...\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Af%28-1%29=a%28-1-i%29%28-1%2Bi%29%28-1-5i%29%281%2B5i%29=52%0D%0A\"\r
\n" ); document.write( "\n" ); document.write( "\"a%28%28-1%29%5E2%2B1%5E2%29%28%28-1%29%5E2%2B5%5E2%29=52\"\r
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\n" ); document.write( "\n" ); document.write( "so that\r
\n" ); document.write( "\n" ); document.write( "\"a%282%29%2826%29=52\"\r
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\n" ); document.write( "\n" ); document.write( "and a=1\r
\n" ); document.write( "\n" ); document.write( "this leads to\r
\n" ); document.write( "\n" ); document.write( "\"%0D%0Af%28x%29=%28x%5E2%2B1%29%28x%5E2%2B25%29=x%5E4%2B26x%5E2%2B25%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E4%2B26x%5E2%2B25%0D%0A\"\r
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