document.write( "Question 763119: How many mL of water should you add to 275 mL of a 9% solution to dilute it down to a 5% solution? \n" ); document.write( "
Algebra.Com's Answer #464489 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! The initial solution contains 9% chemical, C, and 91% water, W, or \n" ); document.write( "(1) C = 0.09*275 or \n" ); document.write( "(2) C = 24.75 mL and \n" ); document.write( "(1) W = .91*275 or \n" ); document.write( "(2) W = 250.25 mL \n" ); document.write( "Now we add some water, w, to yield a solution that is 95% water or \n" ); document.write( "(3) 0.95 = (250.25 + w)/(275 + w) \n" ); document.write( "Remember to add w to both the numerator and denominator. \n" ); document.write( "Cross multiplying (3) gives us \n" ); document.write( "(4) 0.95*(275+w) = 250.25 + w or \n" ); document.write( "(5) 261.25 + 0.95*w = 250.25 + w or \n" ); document.write( "(6) 11 = 0.05*w or \n" ); document.write( "(7) w = 220 mL \n" ); document.write( "Let's check this with chemical of (2) and the total solution. \n" ); document.write( "Is (24.75/(275+220) = 0.05)? \n" ); document.write( "Is (24.75/495 = 0.05)? \n" ); document.write( "Is (0.05 = 0.05)? Yes \n" ); document.write( "Answer: Add 220 mL of water. \n" ); document.write( " |