document.write( "Question 763119: How many mL of water should you add to 275 mL of a 9% solution to dilute it down to a 5% solution? \n" ); document.write( "
Algebra.Com's Answer #464489 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
The initial solution contains 9% chemical, C, and 91% water, W, or
\n" ); document.write( "(1) C = 0.09*275 or
\n" ); document.write( "(2) C = 24.75 mL and
\n" ); document.write( "(1) W = .91*275 or
\n" ); document.write( "(2) W = 250.25 mL
\n" ); document.write( "Now we add some water, w, to yield a solution that is 95% water or
\n" ); document.write( "(3) 0.95 = (250.25 + w)/(275 + w)
\n" ); document.write( "Remember to add w to both the numerator and denominator.
\n" ); document.write( "Cross multiplying (3) gives us
\n" ); document.write( "(4) 0.95*(275+w) = 250.25 + w or
\n" ); document.write( "(5) 261.25 + 0.95*w = 250.25 + w or
\n" ); document.write( "(6) 11 = 0.05*w or
\n" ); document.write( "(7) w = 220 mL
\n" ); document.write( "Let's check this with chemical of (2) and the total solution.
\n" ); document.write( "Is (24.75/(275+220) = 0.05)?
\n" ); document.write( "Is (24.75/495 = 0.05)?
\n" ); document.write( "Is (0.05 = 0.05)? Yes
\n" ); document.write( "Answer: Add 220 mL of water.
\n" ); document.write( "
\n" );