document.write( "Question 63300: solve algebraically: $\"3%5E%282x%2B1%29+=+1%2F243\"$ \n" ); document.write( "

Algebra.Com's Answer #46445 by ntnk(54) $\"\"$ $\"About$

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$\"3%5E%282x%2B1%29+=+1%2F243\"$ \r
\n" ); document.write( "\n" ); document.write( "If x = y, then log x = log y,
\n" ); document.write( "therefore, find the log(base3) of both sides.
\n" ); document.write( "Log(base3)3^(2x+1)=log(base3)(1/243)
\n" ); document.write( "This simplifies to
\n" ); document.write( " $\"2x%2B1=-5\"$ because log(base3)(1/243)=-5
\n" ); document.write( " $\"2x=-6\"$
\n" ); document.write( " $\"2x%2F2=-6%2F2\"$
\n" ); document.write( " $\"x=-3\"$ \r
\n" ); document.write( "\n" ); document.write( "ntnk \n" ); document.write( "

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