document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=763055>Question 763055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by substitution.<BR>\n" );
document.write( "y=2.4x-4.2<BR>\n" );
document.write( "3x+2y=15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464439 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the system by substitution.<BR>\n" );
document.write( "y=2.4x-4.2<BR>\n" );
document.write( "3x+2y=15<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "y is solved for, sub for y in the 2nd equn<BR>\n" );
document.write( "3x + 2y = 15<BR>\n" );
document.write( "3x + 2(2.4x-4.2) = 15<BR>\n" );
document.write( "solve for x, then for y </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );