document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762990>Question 762990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> numerator incresed by 12% & denominator decreased by 2% the value of fraction is 6/7,find original fraction </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464394 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464394\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If x is increased by 12% it is multiplied by 1.12:x + .12x = 1.12x<P><BR>\n" );
document.write( "If y is decreased by 2%, it is multiplied by .98: y -.02y = .98y<P><BR>\n" );
document.write( "1.12x/.98y = 6/7<P><BR>\n" );
document.write( "You can multiply either side by 1 without changing its value.  Multiply the left side by 1 in the form of 100/100 to remove the decimals.<P><BR>\n" );
document.write( "112x/98y = 6/7<P><BR>\n" );
document.write( "Multiply both sides by 98/112.<P><BR>\n" );
document.write( "x/y = 6/7 * 98/112 = 6/7 * 7/8 = 6/8 = 3/4. </SPAN>\n" );
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