document.write( "Question 762872: At 9:45 am Margie threw a ball upwards while standing on a platform 75 ft off of the ground. The trajectory after t seconds follows the equation: h(t) = –0.6t2 + 108t + 75.
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document.write( "a. What will be the maximum height of the ball? __________
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document.write( "b. How long will it take the ball reach its maximum height? __________
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document.write( "c. At what time will the ball hit the ground? _________
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Algebra.Com's Answer #464352 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Margie threw a ball upwards while standing on a platform 75 ft off of the ground. The trajectory after t seconds follows the equation: \n" ); document.write( "h(t) = –0.6t2 + 108t + 75. \n" ); document.write( "--------------------- \n" ); document.write( "b. How long will it take the ball reach its maximum height? \n" ); document.write( "The equation is of a parabola. \n" ); document.write( "The max ht is the vertex. \n" ); document.write( "The vertex is on the axis of symmetry, t = -b/2a \n" ); document.write( "t = -108/(2*-0.6) = 90 seconds \n" ); document.write( "========== \n" ); document.write( "a. What will be the maximum height of the ball? \n" ); document.write( "Max ht = h(90) \n" ); document.write( "= -0.6*90^2 + 108*90 + 75 \n" ); document.write( "= 4935 ft \n" ); document.write( "=========== \n" ); document.write( "c. At what time will the ball hit the ground? \n" ); document.write( "When h(t) = 0 \n" ); document.write( "h(t) = –0.6t^2 + 108t + 75 = 0 \n" ); document.write( "6t^2 - 1080t - 750 = 0 \n" ); document.write( "t^2 - 180t - 125 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "============ \n" ); document.write( "t =~ 180.69 seconds \n" ); document.write( "Ignore the negative solution \n" ); document.write( " \n" ); document.write( " |