document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762930>Question 762930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 0 < p < pi/2 and x=6sin p, what is tan p for the indicated trigonometric function: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+sqrt%2836-x%5E2%29+ ALIGN=MIDDLE  ALT=\"+sqrt%2836-x%5E2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >?\r<BR>\n" );
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document.write( "I have used identities to work the problem down to 6cos p, but I am not sure how to get tangent from that answer. I need your help, please!\r<BR>\n" );
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document.write( "Thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464320 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm with you, I did the same thing, but let's look at it differently. Draw a right triangle with one of the angles with a measure of p degrees. Note p is between 0 and 90 degrees. Now we are given <BR>\n" );
document.write( "(1) x = 6sin(p) or<BR>\n" );
document.write( "(2) sin(p) = x/6<BR>\n" );
document.write( "The side opposite p is x and the hypotheneus is 6. The other side is <BR>\n" );
document.write( "(3) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%286%5E2+-+x%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%286%5E2+-+x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Therefore the tangent of p is<BR>\n" );
document.write( "(4) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28p%29+=+x%2F%28sqrt%286%5E2+-+x%5E2%29%29 ALIGN=MIDDLE  ALT=\"tan%28p%29+=+x%2F%28sqrt%286%5E2+-+x%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "To check this substitute (1) into (4) and get<BR>\n" );
document.write( "(5) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28p%29+=+%286sin%28p%29%29%2F%28sqrt%2836+-+36sin%28p%29%5E2%29%29 ALIGN=MIDDLE  ALT=\"tan%28p%29+=+%286sin%28p%29%29%2F%28sqrt%2836+-+36sin%28p%29%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(6) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28p%29+=+%286sin%28p%29%29%2F%286sqrt%281+-+sin%28p%29%5E2%29%29 ALIGN=MIDDLE  ALT=\"tan%28p%29+=+%286sin%28p%29%29%2F%286sqrt%281+-+sin%28p%29%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(7) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28p%29+=+sin%28p%29%2F%28sqrt%28cos%28p%29%5E2%29%29 ALIGN=MIDDLE  ALT=\"tan%28p%29+=+sin%28p%29%2F%28sqrt%28cos%28p%29%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or<BR>\n" );
document.write( "(8) <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28p%29+=+sin%28p%29%2Fcos%28p%29 ALIGN=MIDDLE  ALT=\"tan%28p%29+=+sin%28p%29%2Fcos%28p%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > QED<BR>\n" );
document.write( "Answer:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28p%29+=+x%2F%28sqrt%286%5E2+-+x%5E2%29%29 ALIGN=MIDDLE  ALT=\"tan%28p%29+=+x%2F%28sqrt%286%5E2+-+x%5E2%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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