document.write( "Question 762909: The Morgans paid $50.40 for 1500 kilowatts hours of electricity one month and $50.80 for 1680 kwh the next month how much should they expect to pay for 1840 kwh? \n" ); document.write( "
Algebra.Com's Answer #464300 by tommyt3rd(5050)\"\" \"About 
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We use the data to determine a line:\r
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\n" ); document.write( "\n" ); document.write( "and using the first pair of data we can write:\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0Ay-1500+=+325%28x-50.40%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "Now when y=1840 we get\r
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\n" ); document.write( "\n" ); document.write( "\"%0D%0A1840-1500+=+450%28x-50.40%29%0D%0A\"\r
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\n" ); document.write( "\n" ); document.write( "When we solve for x we get x=$51.16\r
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