document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762885>Question 762885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars A & B start from the same point at the same time and travel along straight roads that form 60º with each other. After 2 hours, car A has traveled 120km and car B traveled 100km. How far apart are the cars after two hours?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464296 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Arrange in Cartesian points.  Car B travels along the positive x axis from the origin; and car A travels 60 degrees rotated counterclockwise from the origin.  The coordinates for B after two hours are (100, 0).  The coordinates for A after two hours are (120*cos(60), 120*sin(60)).  That is, for A, (120*(1/2), 120*sqrt(3)/2).  Simplifying more, A is at (60, 60*sqrt(3)).\r<BR>\n" );
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document.write( "Now, use the distance formula to find the distance from (100, 0) to (60, 60*sqrt(3)).  I am letting you do that part. </SPAN>\n" );
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