document.write( "Question 762855: The sum of digits of a 2 digit number is 10.The digits of the number interchange their places, when 36 is substracted from the number.Find the two digit number \n" ); document.write( "

Algebra.Com's Answer #464269 by sachi(548) $\"\"$ $\"About$

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The sum of digits of a 2 digit number is 10.
\n" ); document.write( "let the ones digit=x then tenth digit=10-x
\n" ); document.write( "the no is 10[10-x]+x
\n" ); document.write( "when the digits interchange their position the no will be 10x+[10-x]
\n" ); document.write( "The digits of the number interchange their places, when 36 is subtracted from the number.
\n" ); document.write( "so 10x+[10-x]=10[10-x]+x-36
\n" ); document.write( "or 10x+10-x=100-10x+x-36
\n" ); document.write( "or 18x=54
\n" ); document.write( "or x=3
\n" ); document.write( "so the two digit number=10[10-x]+x=10[10-3]+3=73 \n" ); document.write( "

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