document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762790>Question 762790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what would the square footage of surface area of a cone shaped pond that has a radius of 100 ft and is 20 ft deep </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464260 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Surface area of a cone = Pi* r* s<BR>\n" );
document.write( "S = hypotenuse of a right angled<BR>\n" );
document.write( "triangle made up of base = radius<BR>\n" );
document.write( "and upright = height<BR>\n" );
document.write( "20^2 + 100^2 = hypotenuse^2<BR>\n" );
document.write( "      Hypotenuse (s) = 101.98ft<BR>\n" );
document.write( "Surface Area = Pi * 100 * 101.98<BR>\n" );
document.write( "Surface Area = 32,037.96ft^2.<BR>\n" );
document.write( "I have not added Pi*r^2 as the surface of the <BR>\n" );
document.write( "pond is not included in the total.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );