document.write( "Question 762802: Carlisle and Springfield are 100 miles apart. If a car and a train leave Carlisle at the same, and the car travels at a rate of 25mph faster than the train, find the speed of the train if the car takes 2 hours less than the train to Springfield. \r
\n" ); document.write( "\n" ); document.write( "Can't even figure out where to start, should I be using a quadratic equation? Thank you so much!
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Algebra.Com's Answer #464212 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Carlisle and Springfield are 100 miles apart. If a car and a train leave Carlisle at the same, and the car travels at a rate of 25mph faster than the train, find the speed of the train if the car takes 2 hours less than the train to Springfield. \r
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\n" ); document.write( "\n" ); document.write( "Let speed of train be S
\n" ); document.write( "Then speed of car = S + 25
\n" ); document.write( "Time train takes to travel to Springfield = 100/S
\n" ); document.write( "Time car takes to travel to Springfield = 100/(S + 25)\r
\n" ); document.write( "\n" ); document.write( "As time car takes to travel to Springfield is 2 hours less than time taken by train to travel to Springfield, we create a TIME EQUATION, which is:\r
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\n" ); document.write( "\n" ); document.write( "Time taken by car, equals time taken by train, less 2 hours, OR\r
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\n" ); document.write( "\n" ); document.write( "100/(S + 25) = 100/S – 2\r
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\n" ); document.write( "\n" ); document.write( "100S = 100(S + 25) – 2(S)(S + 25) ------ Multiplying by LCD, S(S + 25)\r
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\n" ); document.write( "\n" ); document.write( "\"100S+=+100S+%2B+2500+-+2S%5E2+-+50S\"\r
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\n" ); document.write( "\n" ); document.write( "\"2S%5E2+%2B+100S+-+100S+%2B+50S+-+2500+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2S%5E2+%2B+50S+-+2500+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28S%5E2+%2B+25S+-+1250%29+=+2%280%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"S%5E2+%2B+25S+-+1250+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "(S - 25)(S + 50) = 0\r
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\n" ); document.write( "\n" ); document.write( "S, or speed of train = \"highlight_green%2825%29\" mph OR S = - 50 (ignore)\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!! \r
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\n" ); document.write( "\n" ); document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com
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