document.write( "Question 762782: how to solve i^15 step by step \n" ); document.write( "
Algebra.Com's Answer #464195 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! i^15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i^(12+3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i^(12)*i^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(i^(3*4))*i^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(i^3)^4*i^3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-i)^4*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-1)^4*(i)^4*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-1)^4*(i^2)^2*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-1)^4*(-1)^2*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-1)^4*1*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-1)^4*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1*(-i)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-i\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So i^15 = -i\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Shortcut: divide 15 by 4 to get 3 remainder 3. The remainder of 3 means that i^(15) = i^3. Since i^3 = -i, this means i^15 = -i \n" ); document.write( " |