document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762668>Question 762668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on finding the zeros to this function.... f(x)=x^2+6x+18 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464190 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464190\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the quadratic formula ((-b+ or -sqrt(b^2-4ac))/2a) to solve\r<BR>\n" );
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document.write( "x = (-6+sqrt(36-4*18)) / 2 = (-6+6i) / 2 = 3i-3 = 3(i-1)  where i = sqrt(-1)<BR>\n" );
document.write( "x = (-6-sqrt(36-4*18)) / 2 = (-6-6i) / 2 = -3i-3 = -3(i+1)<BR>\n" );
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