document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762758>Question 762758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a triangle (the sum of its three sides) is 145.one of the sides is twice the length of the smallest side, and the third is five less than three times the smaller side.Find the lenght of each side </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464171 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a triangle (the sum of its three sides) is 145.one of the sides is twice the length of the smallest side, and the third is five less than three times the smaller side.<BR>\n" );
document.write( "Find the length of each side<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "a + b + c = 145<BR>\n" );
document.write( "b = 2a<BR>\n" );
document.write( "c = 3a-5<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "a + 2a + 3a-5 = 145<BR>\n" );
document.write( "6a = 150<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "a = 25<BR>\n" );
document.write( "b = 2a = 50<BR>\n" );
document.write( "c = 3a-5 = 70<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=========== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );