document.write( "Question 65721This question is from textbook An Incremental Development
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\n" ); document.write( "\n" ); document.write( "The square root of 5 - 2\r
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Algebra.Com's Answer #46417 by praseenakos@yahoo.com(507)\"\" \"About 
You can put this solution on YOUR website!
QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "The square root of 5 - 3\r
\n" ); document.write( "\n" ); document.write( "DIVIDED BY \r
\n" ); document.write( "\n" ); document.write( "The square root of 5 - 2\r
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\n" ); document.write( "\n" ); document.write( "ANSWER:\r
\n" ); document.write( "\n" ); document.write( "(sqrt5 - 3)/(sqrt 5-2)\r
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\n" ); document.write( "\n" ); document.write( "Multiply both the numerator and denominator by (sqrt 5 + 2)
\n" ); document.write( "(This step is known as rationalisation. Here what you have to do is consider the denominator and change the sign in between two terms and then multiply both the numerator and denominator with this new binomial. Here denominator is
\n" ); document.write( "sqrt5-2 so we have to multiply sqrt5 + 2 with numerator and denominator.)\r
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\n" ); document.write( "\n" ); document.write( "==> (sqrt5 - 3)*(sqrt 5 + 2)/(sqrt 5-2)* (sqrt 5 + 2)\r
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\n" ); document.write( "\n" ); document.write( "Remove the parenthesis,\r
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\n" ); document.write( "\n" ); document.write( "==>( sqrt 5* sqrt5 + 2*sqrt5 -3sqrt5-3*2)/(sqrt5*sqrt5 +2*sqrt5 -2*sqrt5 -2*2)\r
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\n" ); document.write( "\n" ); document.write( "==> ( 5 -1 sqrt5 -6 )/(5 - 4 )\r
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\n" ); document.write( "\n" ); document.write( "==> (-1-sqrt5)/1\r
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\n" ); document.write( "\n" ); document.write( "==> -1-sqrt5\r
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\n" ); document.write( "\n" ); document.write( "This is the required answer..\r
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\n" ); document.write( "\n" ); document.write( "Hope you understood.\r
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\n" ); document.write( "\n" ); document.write( "Regards.\r
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\n" ); document.write( "\n" ); document.write( "Praseena.\r
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