document.write( "Question 65732This question is from textbook An Incremental Development
\n" ); document.write( ": a\r
\n" ); document.write( "\n" ); document.write( "Divided by\r
\n" ); document.write( "\n" ); document.write( "b + 1 / b + x/c
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Algebra.Com's Answer #46414 by stanbon(75887)\"\" \"About 
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\n" ); document.write( "Divided by\r
\n" ); document.write( "\n" ); document.write( "a/b + 1 / b + x/c\r
\n" ); document.write( "\n" ); document.write( "----------------------------
\n" ); document.write( "[(a/b)+1]/[b+(x/c)]
\n" ); document.write( "=[(a+b)/b]/[bc+x)/c]
\n" ); document.write( "Invert the denominator and multiply to get:\r
\n" ); document.write( "\n" ); document.write( "=[(a+b)/b]
\n" ); document.write( "=[ac+bc]/[b^2c+bs]
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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