document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762671>Question 762671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Line E passes through the points (2, 3) and (4, -3). What is the slope of a line perpendicular to line E?<BR>\n" );
document.write( "            A.-1/3 B.1/3 C.-3 D.3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464123 by </B><A HREF=/tutors/aboutme.mpl?userid=malglu><B>malglu(63)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malglu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> fisrt we need to find the equation of the line.  fill in y=mx +c for both points you know<BR>\n" );
document.write( "3=2m+c<BR>\n" );
document.write( "-3=4m+c\r<BR>\n" );
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document.write( "now solve by simultaneous equations.  first multiply the fisrt equation by 2<BR>\n" );
document.write( "6=4m +2c<BR>\n" );
document.write( "then take away the second equation from this to get<BR>\n" );
document.write( "9=c\r<BR>\n" );
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document.write( "now go back to any of the two equtions, substitute c=9 to get m =-3<BR>\n" );
document.write( "thus the equation is y=-3x +9<BR>\n" );
document.write( "now a line perpendicular to it has a gradient - the gradient , so<BR>\n" );
document.write( "y=3x+9<BR>\n" );
document.write( "so the answer is 3\r<BR>\n" );
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