document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65711>Question 65711</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden area is 30ft long and 20ft wide. A path of uniform width is set around the edge. If the remaining garden area is 400ft^2, what is the width of the path?\r<BR>\n" );
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document.write( "Gosh I am so lost on this one, thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46410 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46410\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A garden area is 30ft long and 20ft wide. A path of uniform width is set around the edge. If the remaining garden area is 400ft^2, what is the width of the path?\r<BR>\n" );
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document.write( "Let x= width of path<BR>\n" );
document.write( "garden area=(l)(w)=(30)(20)=600 sq ft<BR>\n" );
document.write( "remaining garden area=400 sq ft<BR>\n" );
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document.write( "Length of the remaining garden area =(30-2x) ft<BR>\n" );
document.write( "Width of remaining garden area = (20-2x) ft, so\r<BR>\n" );
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document.write( "Eq(1) (30-2x)(20-2x)=400  expanding the factors, we have:<BR>\n" );
document.write( "600-100x+4x^2=400  divide by 4<BR>\n" );
document.write( "150-25x+x^2=100  subtract 100 from each side<BR>\n" );
document.write( "x^2-25x+50=0  factors are:<BR>\n" );
document.write( "Using the quadratic formula(x=(-b+or-sqrt(b^2-4ac))/2a we get\r<BR>\n" );
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document.write( "x=(25+or-sqrt(625-200))/2<BR>\n" );
document.write( "x=(25+or-sqrt(425))/2<BR>\n" );
document.write( "x=(25-20.6)/2<BR>\n" );
document.write( "x=2.2 ft<BR>\n" );
document.write( "x=(25+20.6)/2<BR>\n" );
document.write( "x=22.8 ft Not a solution. It yields negative lengths and widths\r<BR>\n" );
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document.write( "Substitute x=2.2ft in (1) and we get<BR>\n" );
document.write( "(30-4.4)(20-4.4)=400<BR>\n" );
document.write( "(25.6)(15.6)=400<BR>\n" );
document.write( "399+=400\r<BR>\n" );
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document.write( "Hope this helps----ptaylor\r<BR>\n" );
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