document.write( "Question 762571: Mary is 41 years old and her daughter is 9. In how many years will the mother be three times as old as her daughter?
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Algebra.Com's Answer #464074 by josgarithmetic(39617)\"\" \"About 
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y = in how many years...\r
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\n" ); document.write( "\n" ); document.write( "\"41%2By\" and \"9%2By\" are their ages in that passage of years.\r
\n" ); document.write( "\n" ); document.write( "\"%2841%2By%29%2F%289%2By%29=3\"
\n" ); document.write( "Find y.
\n" ); document.write( "\"41%2By=3%28y%2B9%29\"
\n" ); document.write( "\"41%2By=3y%2B27\"
\n" ); document.write( "\"2y=41-27\"
\n" ); document.write( "\"y=7\"
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