document.write( "Question 762581: How do you write an equation in slope- intercept form that satisfies each given condition, if the condition is slope = -5, passes through (-3,-8) \n" ); document.write( "
Algebra.Com's Answer #464069 by ramkikk66(644)\"\" \"About 
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The equation (in slope-intercept form) of a line with slope m and passing through (x1,y1) is\r
\n" ); document.write( "\n" ); document.write( "(y - y1) = m(x - x1)\r
\n" ); document.write( "\n" ); document.write( "Here, m = -5, x1 = -3, y1 = -8\r
\n" ); document.write( "\n" ); document.write( "Substituting the above, the equation for the line is:\r
\n" ); document.write( "\n" ); document.write( "\"%28y+-+%28-8%29%29+=+-5%28x+-+%28-3%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Simplifying\r
\n" ); document.write( "\n" ); document.write( "\"y+%2B+8+=+-5%28x+%2B+3%29\" or\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-5%2Ax+-23\"\r
\n" ); document.write( "\n" ); document.write( "See the equation for the line below.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"5+x+%2B+1+y+=+-23\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-5%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -23/5 = -4.6.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -23/1 = -23.
  • Slope is -5/1 = -5.
  • Equation in slope-intercept form: y=-5*x+-23.
\"graph%28+500%2C+500%2C+-4.6-8%2C+-4.6%2B8%2C+-23-8%2C+-23%2B8%2C+-5%2Ax%2B-23+%29+\"\n" ); document.write( "

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