document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762551>Question 762551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> four times a first number decreased by three times a second number is 22. the sum of the first number and twice the second number 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #464054 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=464054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> four times a first number decreased by three times a second number is 22. the sum of the first number and twice the second number 0<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "1st: a<BR>\n" );
document.write( "2nd: b<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "4a-3b = 22<BR>\n" );
document.write( "a + 2b = 0<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Substitute for \"a\" and solve for \"b\":<BR>\n" );
document.write( "4(-2b)-3b = 22<BR>\n" );
document.write( "-11b = 22<BR>\n" );
document.write( "b = -2<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Solve for \"a\":<BR>\n" );
document.write( "a = -2b<BR>\n" );
document.write( "a = -2*-2 = 4<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===================<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );