document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762459>Question 762459</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve by completing the square\r<BR>\n" );
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document.write( "X^2+2X+48  I believe I would first divide by 2, but not sure what to do after that. Thank you for the help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463980 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we are given x^2 +2x + 48 = 0<BR>\n" );
document.write( "subtract 48 from both sides of the =<BR>\n" );
document.write( "x^2 +2x = -48<BR>\n" );
document.write( "complete the square on the left side of = and add the constant square to the right side<BR>\n" );
document.write( "x^2 +2x + 1 = -48 +1<BR>\n" );
document.write( "(x + 1)^2 = -47<BR>\n" );
document.write( "take the square root of both sides of =<BR>\n" );
document.write( "x + 1 = sqrt(-47)<BR>\n" );
document.write( "x = sqrt(-47) -1<BR>\n" );
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