document.write( "Question 762448: perpendicular to -x + 5y = -6, y-intercept (0,-7) \n" ); document.write( "
Algebra.Com's Answer #463964 by MathLover1(20855)\"\" \"About 
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\"+-x+%2B+5y+=+-6\", \r
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\n" ); document.write( "\n" ); document.write( "\"+-x+%2B+5y+=+-6\"...solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"++5y+=+x-6\"\r
\n" ); document.write( "\n" ); document.write( "\"++y+=+%281%2F5%29x-6%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"++y+=+0.2x-1.2\"\r
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Remember, any two perpendicular lines are negative reciprocals of each other. So if you're given the slope of \"1%2F5\", you can find the perpendicular slope by this formula:
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\n" ); document.write( " \"m%5Bp%5D=-1%2Fm\" where \"m%5Bp%5D\" is the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=-1%2F%281%2F5%29\" So plug in the given slope to find the perpendicular slope
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\n" ); document.write( " \"m%5Bp%5D=%28-1%2F1%29%285%2F1%29\" When you divide fractions, you multiply the first fraction (which is really \"1%2F1\") by the reciprocal of the second
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\n" ); document.write( " \"m%5Bp%5D=-5%2F1\" Multiply the fractions.
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\n" ); document.write( " So the perpendicular slope is \"-5\"
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\n" ); document.write( " So now we know the slope of the unknown line is \"-5\" (its the negative reciprocal of \"1%2F5\" from the line \"y=%281%2F5%29%2Ax%2B6%2F5\").\n" ); document.write( "Also since the unknown line goes through (0,-7), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y%2B7=-5%2A%28x-0%29\" Plug in \"m=-5\", \"x%5B1%5D=0\", and \"y%5B1%5D=-7\"
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\n" ); document.write( " \"y%2B7=-5%2Ax%2B%285%29%280%29\" Distribute \"-5\"
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\n" ); document.write( " \"y%2B7=-5%2Ax-0\" Multiply
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\n" ); document.write( " \"y=-5%2Ax-0-7\"Subtract \"-7\" from both sides to isolate y
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\n" ); document.write( " \"y=-5%2Ax-7\" Combine like terms
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\n" ); document.write( " So the equation of the line that is perpendicular to \"y=%281%2F5%29%2Ax%2B6%2F5\" and goes through (\"0\",\"-7\") is \"y=-5%2Ax-7\"
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\n" ); document.write( " So here are the graphs of the equations \"y=%281%2F5%29%2Ax%2B6%2F5\" and \"y=-5%2Ax-7\"
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\n" ); document.write( " graph of the given equation \"y=%281%2F5%29%2Ax%2B6%2F5\" (red) and graph of the line \"y=-5%2Ax-7\"(green) that is perpendicular to the given graph and goes through (\"0\",\"-7\")
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