document.write( "Question 762375: How many ways are there for four Cricketers, three Swimmers and two Athletes be stand in a line if the same type of sports persons stand together? \n" ); document.write( "
Algebra.Com's Answer #463946 by ramkikk66(644) ![]() You can put this solution on YOUR website! Since the people of one sport should stand together, let us consider all 4 cricketers as one unit C, 3 swimmers as one unit S, 2 Athletes as one unit A.\r \n" ); document.write( "\n" ); document.write( "So we have 3 units which can be arranged in 3! or 6 ways. \n" ); document.write( "(CSA, CAS, ASC, ACS, SCA, SAC)\r \n" ); document.write( "\n" ); document.write( "(Note: The expression n! (read as n-factorial is evaluated as 1*2*3...*n. \n" ); document.write( "3! = 1*2*3 = 6)\r \n" ); document.write( "\n" ); document.write( "Moreover, within each unit, the players can stand in all possible permutations. \n" ); document.write( "4 cricketers can stand in 4! = 24 ways \n" ); document.write( "3 swimmers can stand in 3! = 6 ways \n" ); document.write( "2 swimmers can stand in 2! = 2 ways.\r \n" ); document.write( "\n" ); document.write( "Hence the total number of ways = 6*24*6*2 = 1728 ways.\r \n" ); document.write( "\n" ); document.write( "Hope this helps.\r \n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( " |