document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65712>Question 65712</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1cm longer than its width. If the diagonal of the rectangle is 4cm, what are the dimensions (length and width) of the rectangle?\r<BR>\n" );
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document.write( "Talk about confusing to me! Thank you for the help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #46392 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=46392\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width = w<BR>\n" );
document.write( "length = w + 1<BR>\n" );
document.write( "A width and a length can make legs of a right triangle with the diagonal being its hypotenuse. *Draw a picture to better understand.<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "(w)^2 + (w + 1)^2 = 4^2<BR>\n" );
document.write( "w^2 + w^2 + 2w + 1 = 16<BR>\n" );
document.write( "2w^2 + 2w = 15<BR>\n" );
document.write( "w^2 + w = 7.5<BR>\n" );
document.write( "(w + 0.5)^2 = 7.75<BR>\n" );
document.write( "w + 0.5 = +- sqrt(7.75)<BR>\n" );
document.write( "w = -0.5 +- sqrt(7.75)<BR>\n" );
document.write( "width about 2.2839<BR>\n" );
document.write( "length about 3.2839<BR>\n" );
document.write( "*You can use other ways to solve: w^2 + w - 7.5 = 0 </SPAN>\n" );
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