document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762408>Question 762408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide 534 into three parts such tht the second part will be 32 less thn twice the first & third wil be 18 more than the first. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463918 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First part = x<BR>\n" );
document.write( "Second part = 2x - 32<BR>\n" );
document.write( "Third part = 18 + x<BR>\n" );
document.write( "x + (2x - 32) + (18 + x) = 534<BR>\n" );
document.write( "                   4x -14 = 534<BR>\n" );
document.write( "                        4x = 548<BR>\n" );
document.write( "                         x = 137<BR>\n" );
document.write( "First part = 137<BR>\n" );
document.write( "Second part = 242<BR>\n" );
document.write( "Third part = 155<BR>\n" );
document.write( "     Total 534.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );