document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=762398>Question 762398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> there are three vertices of a triangle (-4,5),(-4,-3) and (2,3) give the length of the longest side  enter answer as a simplified ratical </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #463916 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=463916\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance = Square root of(x2 - x1)^2+ (y2 - y1)^2<BR>\n" );
document.write( "(-4,5) (-4,-3)  Sqrt(-4-(-4))^2 + (-3-5)^2<BR>\n" );
document.write( "                Sqrt(0)^2 + (-8)^2<BR>\n" );
document.write( "              = Sqrt 64 = 8 units<BR>\n" );
document.write( "(-4,-3)  (2,3)  Sqrt(2-(-4)^2 + (3 -(-3)^2<BR>\n" );
document.write( "                Sqrt (6)^2 + (6^2)<BR>\n" );
document.write( "                Sqrt 36 + 36<BR>\n" );
document.write( "                Sqrt 72  = 6sqrt2<BR>\n" );
document.write( "(-4,5)  (2,3)   Sqrt (2-(-4)^2 + (3 - 5)^2<BR>\n" );
document.write( "                Sqrt (6)^2 + (-2)^2<BR>\n" );
document.write( "                Sqrt 36 + 4<BR>\n" );
document.write( "                Sqrt 40 = 2sqrt10\r<BR>\n" );
document.write( "\n" );
document.write( "Longest side = 6sqrt2.<BR>\n" );
document.write( "Hope this helps<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );