document.write( "Question 762367: I stand on a building 640 feet high and throw a rock into the air with a velocity of 96 ft/sec. When does the rock have a height of 800 feet? \n" ); document.write( "
Algebra.Com's Answer #463900 by stanbon(75887)\"\" \"About 
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I stand on a building 640 feet high and throw a rock into the air with a velocity of 96 ft/sec. When does the rock have a height of 800 feet?
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\n" ); document.write( "h(t) = -16t^2 + 96t + 640
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\n" ); document.write( "Solve:
\n" ); document.write( "-16t^2 + 96t + 640 = 800
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\n" ); document.write( "-16t^2 + 96t - 160 = 0
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\n" ); document.write( "-16(t^2 - 6t + 10) = 0
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\n" ); document.write( "Quadratic formula:
\n" ); document.write( "t = [6 +- sqrt(36-4*10)]/(2)
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\n" ); document.write( "Since 36-4*10 is negative there is no Real Number solution.
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\n" ); document.write( "The rock never teaches a height of 800 ft.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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