document.write( "Question 762351: x^2+xy=5, y^2+xy=3 \n" ); document.write( "
Algebra.Com's Answer #463875 by dkppathak(439)\"\" \"About 
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x^2+xy=5,(i)
\n" ); document.write( " y^2+xy=3(ii)
\n" ); document.write( "taking x and y common from i and ii
\n" ); document.write( "x(x+y)=5 y(y+x)=3
\n" ); document.write( "x+y=5/x(iii) and x+y=3/y(iv)
\n" ); document.write( "from these equations
\n" ); document.write( "5/x=3/y
\n" ); document.write( "y=3x/5
\n" ); document.write( "putting the value of y in equation (iii)
\n" ); document.write( "x(x+3x/5)=5
\n" ); document.write( "x(8x/5)=5
\n" ); document.write( "8x^2=25
\n" ); document.write( "x^2=25/8
\n" ); document.write( "x=sqrt 25/8
\n" ); document.write( "simlarly
\n" ); document.write( "we can find x=5y/3
\n" ); document.write( "putting value in (iv)
\n" ); document.write( "y(y+5y/3)=3
\n" ); document.write( "8y^2=9
\n" ); document.write( "y^2=9/8
\n" ); document.write( "y=sqrt 9/8
\n" ); document.write( "answer x=sqrt25/8
\n" ); document.write( "y=sqrt 9/8\r
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