document.write( "Question 762291: June, an owner of a coffee stand, marked down the price of a latte between 7:00 A.M. and 8:00 A.M. from $2.00 a cup. If she grossed $98.69 from the latte sale and we know that she never sells a latte for less than a dollar, how many lattes did she sell between 7:00 A.M. and 8:00 A.M.? Explain your reasoning \n" ); document.write( "
Algebra.Com's Answer #463869 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Originally price was $2.00 per cup but was then reduced to 2-d per cup using d as the amount discounted.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Unknown is, how many cups of this latte were sold. Call the number, n.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The answer is between two inclusive extremes. \n" ); document.write( "(2-0.01)n=98.69 and 1*n=98.69\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Need the whole number n between 1.99n=98.69 and 1*n=98.69. \n" ); document.write( "Anything even near the 1$/latte value will not do, selling one or two or so few latte's should not be expected to achieve revenue over 90 dollars. \n" ); document.write( "Looking at the other end, from the (2-0.01)n limit gives easily more meaningful possibilities.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Not being able to find an efficient algebraic way to solve this, I resorted to a simple BASIC program and this program shows 71 cups of latte at $1.39 per latte to be the best answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Program used was this code: \n" ); document.write( "for i=1 to 99 \n" ); document.write( "n=98.69/((99+i)/100) \n" ); document.write( "print n;\" \";(99+i)/100 \n" ); document.write( "next i\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |