document.write( "Question 762291: June, an owner of a coffee stand, marked down the price of a latte between 7:00 A.M. and 8:00 A.M. from $2.00 a cup. If she grossed $98.69 from the latte sale and we know that she never sells a latte for less than a dollar, how many lattes did she sell between 7:00 A.M. and 8:00 A.M.? Explain your reasoning \n" ); document.write( "
Algebra.Com's Answer #463869 by josgarithmetic(39618)\"\" \"About 
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Originally price was $2.00 per cup but was then reduced to 2-d per cup using d as the amount discounted.\r
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\n" ); document.write( "\n" ); document.write( "Unknown is, how many cups of this latte were sold. Call the number, n.\r
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\n" ); document.write( "\n" ); document.write( "\"%282-d%29%2An=98.69\", and \"1.00%3C2-d\" as expected condition. This condition is the same as \"d%3E0\" and \"d%3C1\", or \"0%3Cd%3C1\".\r
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\n" ); document.write( "\n" ); document.write( "The answer is between two inclusive extremes.
\n" ); document.write( "(2-0.01)n=98.69 and 1*n=98.69\r
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\n" ); document.write( "\n" ); document.write( "Need the whole number n between 1.99n=98.69 and 1*n=98.69.
\n" ); document.write( "Anything even near the 1$/latte value will not do, selling one or two or so few latte's should not be expected to achieve revenue over 90 dollars.
\n" ); document.write( "Looking at the other end, from the (2-0.01)n limit gives easily more meaningful possibilities.\r
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\n" ); document.write( "\n" ); document.write( "Not being able to find an efficient algebraic way to solve this, I resorted to a simple BASIC program and this program shows 71 cups of latte at $1.39 per latte to be the best answer.\r
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\n" ); document.write( "\n" ); document.write( "Program used was this code:
\n" ); document.write( "for i=1 to 99
\n" ); document.write( "n=98.69/((99+i)/100)
\n" ); document.write( "print n;\" \";(99+i)/100
\n" ); document.write( "next i\r
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