document.write( "Question 762311: a rectangle field measure 24ft by 100ft part of the lawn is torn up to install a walk to uniform width around it the area of the new field is one half the area how wide is the walk ? could someone help me please \n" ); document.write( "
Algebra.Com's Answer #463857 by josgarithmetic(39620)\"\" \"About 
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Area before new walkway is 24*100 sq. ft. This will also be the combined areas of the new, remaining field and the new walkway. \r
\n" ); document.write( "\n" ); document.write( "New field will be area of \"%2824-2w%29%28100-2w%29\" sq. ft. using w as the width of the walkway.\r
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\n" ); document.write( "\n" ); document.write( "New field is half the area of the original field:
\n" ); document.write( "\"highlight%28%281%2F2%29%282400%29=%2824-2w%29%28100-2w%29%29\"
\n" ); document.write( "Find w.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1200=4%2812-w%29%2850-w%29\"
\n" ); document.write( "\"300=%2812-w%29%2850-w%29\"
\n" ); document.write( ".
\n" ); document.write( "\"w%5E2-62w%2B300=0\"
\n" ); document.write( "\"w=%2862%2B2%2Asqrt%28661%29%29%2F2\"
\n" ); document.write( "\"highlight%28w=31%2Bsqrt%28661%29%29\"
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